Hi, some time ago I started learn Java language. I am trying to self-study and learn Java. And I have to say that the language is very nice, and with deep knowledge of C#, my progress is fast. I want to show you today here one of the nice code puzzle solutions named Tag Content Extractor. It takes me some time. I started learning Java from straightforward puzzles, and every next one became more and more complicated. Also, I am thinking about Java certification. However, it is not a must because I get the lesson that certification in .NET, even MCPD Enterprise Application Developer, does not return any career opportunity, so I think certification is not very important. But maybe some basic steps could be helpful. And I think every good Software Architect should know at least C# and Java. I know that one of those languages could be the main and second well-known only to understand software solutions better. Below you can find the solution to the mentioned puzzle. And if you are interested to learn Java with deep knowledge of C#, you can go to this very nice how-to . On the Hacker Rank I get so far from Java language trainings 248 points and 3199 rank :).
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution{
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int testCases = Integer.parseInt(in.nextLine());
Pattern pattern = Pattern.compile(
"<([/a-zA-Z]+).*?>"
);
while(testCases>0) {
String line = in.nextLine();
Matcher matcher = pattern.matcher(line);
List<String> tags = new ArrayList<String>();
while(matcher.find()) {
String tag = matcher.group(0);
tags.add(tag);
}
boolean none = true;
while(tags.size() >= 2) {
String tagB = tags.get(0);
String tagE = tags.get(1);
if (!tagB.replace("<", "</").equals(tagE)) {
tags.remove(0);
int x = line.indexOf(tagB);
line = line.substring(x + tagB.length());
}
else {
tags.remove(0);
tags.remove(0);
int x = line.indexOf(tagB) + tagB.length();
int y = line.indexOf(tagE, x);
String finding = line.substring(x,y);
line = line.substring(y + tagE.length());
if (!finding.isEmpty()) {
System.out.println(finding);
none = false;
}
}
}
if (none) {
System.out.println("None");
}
testCases--;
}
}
}
Thanks for reading and enjoy! It is still 50 lines, and there is probably a way to use regex matcher to find out texts quicker, but this is the best I can do right now with my level of Java knowledge!
p ;).